Xenolord + Splatterina = Jormuntide
In Palworld 1.0, breeding Xenolord with Splatterina hatches Jormuntide. The result comes from the 1.0 breeding formula, shown in full below.
Palworld 1.0 · build 24575149 · verified against the full 44,551-pair breeding table
JormuntideWhy Jormuntide? The formula
Each Pal has a hidden breeding power (CombiRank). The child is the formula-pool Pal closest to the parents' average: (Xenolord 400 + Splatterina 780 + 1) / 2 = target 590. Jormuntide's power is 590 — the closest match in the pool. On an exact tie the game picks the higher-power Pal.
Easiest other ways to breed Jormuntide
Bastigor + Omasculboth parents wild-caughtShaolong + Omasculboth parents wild-caughtSelyne + Lapureboth parents wild-caughtPanthalus + Omasculboth parents wild-caughtBellanoir Libero + Grizzboltboth parents wild-caught
Frostallion + Grizzboltboth parents wild-caught
Neptilius + Grizzboltboth parents wild-caught
Neptilius + Xenogardboth parents wild-caught
210 pairs in total produce Jormuntide in 1.0. The full list lives on the Jormuntide page.
Plan the full route
Need Jormuntide from scratch — or a god-roll with the right passives and IVs? The planner walks the whole tree from wild-caught parents.
Open the breeding planner